10113311551 has 4 divisors (see below), whose sum is σ = 11558070352. Its totient is φ = 8668552752.

The previous prime is 10113311519. The next prime is 10113311557. The reversal of 10113311551 is 15511331101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10113311551 - 2⁵ = 10113311519 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113311557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 722379390 + ... + 722379403.

It is an arithmetic number, because the mean of its divisors is an integer number (2889517588).

Almost surely, 2^10113311551 is an apocalyptic number.

10113311551 is a deficient number, since it is larger than the sum of its proper divisors (1444758801).

10113311551 is an equidigital number, since it uses as much as digits as its factorization.

10113311551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1444758800.

The product of its (nonzero) digits is 225, while the sum is 22.

Adding to 10113311551 its reverse (15511331101), we get a palindrome (25624642652).

The spelling of 10113311551 in words is "ten billion, one hundred thirteen million, three hundred eleven thousand, five hundred fifty-one".