Base | Representation |
---|---|
bin | 10110111111101011100011… |
… | …110100101110100111110111 |
3 | 111021002020021011122111111111 |
4 | 112333223203310232213313 |
5 | 101223431113240431403 |
6 | 555031525344015451 |
7 | 30205425022013545 |
oct | 2677534364564767 |
9 | 437066234574444 |
10 | 101133122202103 |
11 | 2a251352a47912 |
12 | b41433a001587 |
13 | 4457a740b5b74 |
14 | 1ad8c2525ad95 |
15 | ba5a8802b56d |
hex | 5bfae3d2e9f7 |
101133122202103 has 12 divisors (see below), whose sum is σ = 110647819460880. Its totient is φ = 92113659675840.
The previous prime is 101133122202097. The next prime is 101133122202143. The reversal of 101133122202103 is 301202221331101.
It is not a de Polignac number, because 101133122202103 - 245 = 65948750113271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101133122202143) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3095200723 + ... + 3095233396.
It is an arithmetic number, because the mean of its divisors is an integer number (9220651621740).
Almost surely, 2101133122202103 is an apocalyptic number.
101133122202103 is a deficient number, since it is larger than the sum of its proper divisors (9514697258777).
101133122202103 is an equidigital number, since it uses as much as digits as its factorization.
101133122202103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6190434198 (or 6190434167 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 101133122202103 its reverse (301202221331101), we get a palindrome (402335343533204).
The spelling of 101133122202103 in words is "one hundred one trillion, one hundred thirty-three billion, one hundred twenty-two million, two hundred two thousand, one hundred three".
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