1011332043431 has 4 divisors (see below), whose sum is σ = 1046205562200. Its totient is φ = 976458524664.

The previous prime is 1011332043419. The next prime is 1011332043439. The reversal of 1011332043431 is 1343402331101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011332043431 is a prime.

It is a super-2 number, since 2×1011332043431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1011332043431.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011332043439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17436759341 + ... + 17436759398.

It is an arithmetic number, because the mean of its divisors is an integer number (261551390550).

Almost surely, 2^{1011332043431} is an apocalyptic number.

1011332043431 is a deficient number, since it is larger than the sum of its proper divisors (34873518769).

1011332043431 is an equidigital number, since it uses as much as digits as its factorization.

1011332043431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34873518768.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1011332043431 its reverse (1343402331101), we get a palindrome (2354734374532).

The spelling of 1011332043431 in words is "one trillion, eleven billion, three hundred thirty-two million, forty-three thousand, four hundred thirty-one".