Base | Representation |
---|---|
bin | 11101011011110001001… |
… | …01110110100000001111 |
3 | 10120200110001120200002201 |
4 | 32231320211312200033 |
5 | 113032211132044210 |
6 | 2052334200502331 |
7 | 133031650303111 |
oct | 16557045664017 |
9 | 3520401520081 |
10 | 1011340503055 |
11 | 35a9a8391773 |
12 | 144007a7a9a7 |
13 | 744a490278c |
14 | 36d406313b1 |
15 | 1b49216553a |
hex | eb7897680f |
1011340503055 has 8 divisors (see below), whose sum is σ = 1215264281472. Its totient is φ = 807968617248.
The previous prime is 1011340503011. The next prime is 1011340503067. The reversal of 1011340503055 is 5503050431101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1011340503055 - 219 = 1011339978767 is a prime.
It is a super-2 number, since 2×10113405030552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 137969119 + ... + 137976448.
It is an arithmetic number, because the mean of its divisors is an integer number (151908035184).
Almost surely, 21011340503055 is an apocalyptic number.
1011340503055 is a deficient number, since it is larger than the sum of its proper divisors (203923778417).
1011340503055 is an equidigital number, since it uses as much as digits as its factorization.
1011340503055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 275946305.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 1011340503055 its reverse (5503050431101), we get a palindrome (6514390934156).
The spelling of 1011340503055 in words is "one trillion, eleven billion, three hundred forty million, five hundred three thousand, fifty-five".
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