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1011341341355 = 5202268268271
BaseRepresentation
bin11101011011110001010…
…01000011001010101011
310120200110010011021000212
432231320221003022223
5113032211340410410
62052334230451335
7133031660364122
oct16557051031253
93520403137025
101011341341355
1135a9a8904584
12144008203b4b
13744a4b37207
1436d407acab9
151b49227db05
hexeb78a432ab

1011341341355 has 4 divisors (see below), whose sum is σ = 1213609609632. Its totient is φ = 809073073080.

The previous prime is 1011341341343. The next prime is 1011341341391. The reversal of 1011341341355 is 5531431431101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1011341341355 - 224 = 1011324564139 is a prime.

It is a super-2 number, since 2×10113413413552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101134134131 + ... + 101134134140.

It is an arithmetic number, because the mean of its divisors is an integer number (303402402408).

Almost surely, 21011341341355 is an apocalyptic number.

1011341341355 is a deficient number, since it is larger than the sum of its proper divisors (202268268277).

1011341341355 is an equidigital number, since it uses as much as digits as its factorization.

1011341341355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 202268268276.

The product of its (nonzero) digits is 10800, while the sum is 32.

Adding to 1011341341355 its reverse (5531431431101), we get a palindrome (6542772772456).

The spelling of 1011341341355 in words is "one trillion, eleven billion, three hundred forty-one million, three hundred forty-one thousand, three hundred fifty-five".

Divisors: 1 5 202268268271 1011341341355