1011342331423 has 4 divisors (see below), whose sum is σ = 1012272730240. Its totient is φ = 1010411932608.

The previous prime is 1011342331379. The next prime is 1011342331427. The reversal of 1011342331423 is 3241332431101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1011342331423 - 2²¹ = 1011340234271 is a prime.

It is a super-2 number, since 2×1011342331423² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011342331391 and 1011342331400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011342331427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465197778 + ... + 465199951.

It is an arithmetic number, because the mean of its divisors is an integer number (253068182560).

Almost surely, 2^{1011342331423} is an apocalyptic number.

1011342331423 is a deficient number, since it is larger than the sum of its proper divisors (930398817).

1011342331423 is an equidigital number, since it uses as much as digits as its factorization.

1011342331423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 930398816.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1011342331423 its reverse (3241332431101), we get a palindrome (4252674762524).

The spelling of 1011342331423 in words is "one trillion, eleven billion, three hundred forty-two million, three hundred thirty-one thousand, four hundred twenty-three".