10113451 has 4 divisors (see below), whose sum is σ = 10120032. Its totient is φ = 10106872.

The previous prime is 10113443. The next prime is 10113461. The reversal of 10113451 is 15431101.

10113451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 15431101 = 7 ⋅2204443.

It is a cyclic number.

It is not a de Polignac number, because 10113451 - 2³ = 10113443 is a prime.

It is a super-2 number, since 2×10113451² = 204563782258802, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10113401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 381 + ... + 4513.

It is an arithmetic number, because the mean of its divisors is an integer number (2530008).

Almost surely, 2^10113451 is an apocalyptic number.

10113451 is a deficient number, since it is larger than the sum of its proper divisors (6581).

10113451 is an equidigital number, since it uses as much as digits as its factorization.

10113451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6580.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 10113451 is about 3180.1652472788. The cubic root of 10113451 is about 216.2551497320.

Adding to 10113451 its reverse (15431101), we get a palindrome (25544552).

The spelling of 10113451 in words is "ten million, one hundred thirteen thousand, four hundred fifty-one".