10113401 has 2 divisors, whose sum is σ = 10113402. Its totient is φ = 10113400.

The previous prime is 10113359. The next prime is 10113437. The reversal of 10113401 is 10431101.

10113401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9759376 + 354025 = 3124^2 + 595^2 .

It is an emirp because it is prime and its reverse (10431101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10113401 - 2²² = 5919097 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10113461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056700 + 5056701.

It is an arithmetic number, because the mean of its divisors is an integer number (5056701).

Almost surely, 2^10113401 is an apocalyptic number.

It is an amenable number.

10113401 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113401 is an equidigital number, since it uses as much as digits as its factorization.

10113401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 10113401 is about 3180.1573860424. The cubic root of 10113401 is about 216.2547933494.

Adding to 10113401 its reverse (10431101), we get a palindrome (20544502).

The spelling of 10113401 in words is "ten million, one hundred thirteen thousand, four hundred one".