10114000403 has 8 divisors (see below), whose sum is σ = 10908844128. Its totient is φ = 9321562944.

The previous prime is 10114000399. The next prime is 10114000439. The reversal of 10114000403 is 30400041101.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10114000403 - 2² = 10114000399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10114000493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 592826 + ... + 609647.

It is an arithmetic number, because the mean of its divisors is an integer number (1363605516).

Almost surely, 2^10114000403 is an apocalyptic number.

10114000403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

10114000403 is a deficient number, since it is larger than the sum of its proper divisors (794843725).

10114000403 is a wasteful number, since it uses less digits than its factorization.

10114000403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1203133.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 10114000403 its reverse (30400041101), we get a palindrome (40514041504).

The spelling of 10114000403 in words is "ten billion, one hundred fourteen million, four hundred three", and thus it is an aban number.