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10114011053 = 23439739611
BaseRepresentation
bin10010110101101011…
…11000111110101101
3222002212021222212222
421122311320332231
5131203141323203
64351334205125
7505430450456
oct113265707655
928085258788
1010114011053
114320106223
121b631b37a5
13c524c8433
146bd36012d
153e2dce038
hex25ad78fad

10114011053 has 4 divisors (see below), whose sum is σ = 10553750688. Its totient is φ = 9674271420.

The previous prime is 10114011043. The next prime is 10114011071. The reversal of 10114011053 is 35011041101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10114011053 - 212 = 10114006957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10114011043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219869783 + ... + 219869828.

It is an arithmetic number, because the mean of its divisors is an integer number (2638437672).

Almost surely, 210114011053 is an apocalyptic number.

It is an amenable number.

10114011053 is a deficient number, since it is larger than the sum of its proper divisors (439739635).

10114011053 is an equidigital number, since it uses as much as digits as its factorization.

10114011053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 439739634.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 10114011053 its reverse (35011041101), we get a palindrome (45125052154).

The spelling of 10114011053 in words is "ten billion, one hundred fourteen million, eleven thousand, fifty-three".

Divisors: 1 23 439739611 10114011053