10114024442433 has 4 divisors (see below), whose sum is σ = 13485365923248. Its totient is φ = 6742682961620.

The previous prime is 10114024442413. The next prime is 10114024442449. The reversal of 10114024442433 is 33424442041101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10114024442433 - 2¹⁸ = 10114024180289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10114024442394 and 10114024442403.

It is not an unprimeable number, because it can be changed into a prime (10114024442413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685670740403 + ... + 1685670740408.

It is an arithmetic number, because the mean of its divisors is an integer number (3371341480812).

Almost surely, 2^{10114024442433} is an apocalyptic number.

It is an amenable number.

10114024442433 is a deficient number, since it is larger than the sum of its proper divisors (3371341480815).

10114024442433 is an equidigital number, since it uses as much as digits as its factorization.

10114024442433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3371341480814.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 10114024442433 its reverse (33424442041101), we get a palindrome (43538466483534).

The spelling of 10114024442433 in words is "ten trillion, one hundred fourteen billion, twenty-four million, four hundred forty-two thousand, four hundred thirty-three".