10114035303 has 4 divisors (see below), whose sum is σ = 13485380408. Its totient is φ = 6742690200.

The previous prime is 10114035247. The next prime is 10114035313. The reversal of 10114035303 is 30353041101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10114035303 - 2¹⁰ = 10114034279 is a prime.

It is a super-2 number, since 2×10114035303² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10114035303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10114035313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685672548 + ... + 1685672553.

It is an arithmetic number, because the mean of its divisors is an integer number (3371345102).

Almost surely, 2^10114035303 is an apocalyptic number.

10114035303 is a deficient number, since it is larger than the sum of its proper divisors (3371345105).

10114035303 is an equidigital number, since it uses as much as digits as its factorization.

10114035303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3371345104.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 10114035303 its reverse (30353041101), we get a palindrome (40467076404).

The spelling of 10114035303 in words is "ten billion, one hundred fourteen million, thirty-five thousand, three hundred three".