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1011412433113 = 29160632171219
BaseRepresentation
bin11101011011111001110…
…00001111100011011001
310120200122001221002120221
432231330320033203121
5113032333040324423
62052345250320041
7133033512555535
oct16557470174331
93520561832527
101011412433113
1135aa34a508a5
12144027b89021
13744b6798944
1436d49dd6bc5
151b498622e5d
hexeb7ce0f8d9

1011412433113 has 8 divisors (see below), whose sum is σ = 1046354342400. Its totient is φ = 976474898448.

The previous prime is 1011412433093. The next prime is 1011412433147. The reversal of 1011412433113 is 3113342141101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1011412433113 - 213 = 1011412424921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1011412433413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 619783 + ... + 1551436.

It is an arithmetic number, because the mean of its divisors is an integer number (130794292800).

Almost surely, 21011412433113 is an apocalyptic number.

It is an amenable number.

1011412433113 is a deficient number, since it is larger than the sum of its proper divisors (34941909287).

1011412433113 is a wasteful number, since it uses less digits than its factorization.

1011412433113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2187311.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1011412433113 its reverse (3113342141101), we get a palindrome (4124754574214).

The spelling of 1011412433113 in words is "one trillion, eleven billion, four hundred twelve million, four hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 29 16063 465827 2171219 62965351 34876290797 1011412433113