1011431244003 has 4 divisors (see below), whose sum is σ = 1348574992008. Its totient is φ = 674287496000.

The previous prime is 1011431243939. The next prime is 1011431244023. The reversal of 1011431244003 is 3004421341101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1011431244003 - 2⁶ = 1011431243939 is a prime.

It is a super-2 number, since 2×1011431244003² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1011431244023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168571873998 + ... + 168571874003.

It is an arithmetic number, because the mean of its divisors is an integer number (337143748002).

Almost surely, 2^{1011431244003} is an apocalyptic number.

1011431244003 is a deficient number, since it is larger than the sum of its proper divisors (337143748005).

1011431244003 is an equidigital number, since it uses as much as digits as its factorization.

1011431244003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 337143748004.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1011431244003 its reverse (3004421341101), we get a palindrome (4015852585104).

The spelling of 1011431244003 in words is "one trillion, eleven billion, four hundred thirty-one million, two hundred forty-four thousand, three".