1011432444131 has 4 divisors (see below), whose sum is σ = 1011738849264. Its totient is φ = 1011126039000.

The previous prime is 1011432444073. The next prime is 1011432444133. The reversal of 1011432444131 is 1314442341101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1011432444131 - 2¹⁸ = 1011432181987 is a prime.

It is a super-2 number, since 2×1011432444131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011432444094 and 1011432444103.

It is not an unprimeable number, because it can be changed into a prime (1011432444133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153197615 + ... + 153204216.

It is an arithmetic number, because the mean of its divisors is an integer number (252934712316).

Almost surely, 2^{1011432444131} is an apocalyptic number.

1011432444131 is a deficient number, since it is larger than the sum of its proper divisors (306405133).

1011432444131 is an equidigital number, since it uses as much as digits as its factorization.

1011432444131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 306405132.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 1011432444131 its reverse (1314442341101), we get a palindrome (2325874785232).

The spelling of 1011432444131 in words is "one trillion, eleven billion, four hundred thirty-two million, four hundred forty-four thousand, one hundred thirty-one".