10114404344113 has 4 divisors (see below), whose sum is σ = 10114411552768. Its totient is φ = 10114397135460.

The previous prime is 10114404343999. The next prime is 10114404344119. The reversal of 10114404344113 is 31144340441101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10114404344113 is a prime.

It is a super-3 number, since 3×10114404344113³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10114404344119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 741993 + ... + 4558438.

It is an arithmetic number, because the mean of its divisors is an integer number (2528602888192).

Almost surely, 2^{10114404344113} is an apocalyptic number.

It is an amenable number.

10114404344113 is a deficient number, since it is larger than the sum of its proper divisors (7208655).

10114404344113 is an equidigital number, since it uses as much as digits as its factorization.

10114404344113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7208654.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 10114404344113 its reverse (31144340441101), we get a palindrome (41258744785214).

The spelling of 10114404344113 in words is "ten trillion, one hundred fourteen billion, four hundred four million, three hundred forty-four thousand, one hundred thirteen".