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1011513341 = 3832641027
BaseRepresentation
bin111100010010100…
…111011111111101
32121111100012110002
4330102213133331
54032421411331
6244212124045
734031502326
oct7422473775
92544305402
101011513341
11479a77a43
12242906625
1313173b807
14984a744d
155dc079cb
hex3c4a77fd

1011513341 has 4 divisors (see below), whose sum is σ = 1014154752. Its totient is φ = 1008871932.

The previous prime is 1011513323. The next prime is 1011513361. The reversal of 1011513341 is 1433151101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011513341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011513361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320131 + ... + 1320896.

It is an arithmetic number, because the mean of its divisors is an integer number (253538688).

Almost surely, 21011513341 is an apocalyptic number.

It is an amenable number.

1011513341 is a deficient number, since it is larger than the sum of its proper divisors (2641411).

1011513341 is an equidigital number, since it uses as much as digits as its factorization.

1011513341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2641410.

The product of its (nonzero) digits is 180, while the sum is 20.

The square root of 1011513341 is about 31804.2975240768. The cubic root of 1011513341 is about 1003.8231452667.

Adding to 1011513341 its reverse (1433151101), we get a palindrome (2444664442).

The spelling of 1011513341 in words is "one billion, eleven million, five hundred thirteen thousand, three hundred forty-one".

Divisors: 1 383 2641027 1011513341