101200022113 has 4 divisors (see below), whose sum is σ = 101200815108. Its totient is φ = 101199229120.

The previous prime is 101200022101. The next prime is 101200022123. The reversal of 101200022113 is 311220002101.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 311220002101 = 17327 ⋅17961563.

It can be written as a sum of positive squares in 2 ways, for example, as 2058164689 + 99141857424 = 45367^2 + 314868^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101200022113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101200022093 and 101200022102.

It is not an unprimeable number, because it can be changed into a prime (101200022123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156748 + ... + 476413.

It is an arithmetic number, because the mean of its divisors is an integer number (25300203777).

Almost surely, 2^101200022113 is an apocalyptic number.

It is an amenable number.

101200022113 is a deficient number, since it is larger than the sum of its proper divisors (792995).

101200022113 is an equidigital number, since it uses as much as digits as its factorization.

101200022113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 792994.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 101200022113 its reverse (311220002101), we get a palindrome (412420024214).

The spelling of 101200022113 in words is "one hundred one billion, two hundred million, twenty-two thousand, one hundred thirteen".