101200024111 has 4 divisors (see below), whose sum is σ = 103668317424. Its totient is φ = 98731730800.

The previous prime is 101200024103. The next prime is 101200024139. The reversal of 101200024111 is 111420002101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111420002101 = 149 ⋅747785249.

It is a cyclic number.

It is not a de Polignac number, because 101200024111 - 2³ = 101200024103 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101200024091 and 101200024100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101200024411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1234146595 + ... + 1234146676.

It is an arithmetic number, because the mean of its divisors is an integer number (25917079356).

Almost surely, 2^101200024111 is an apocalyptic number.

101200024111 is a deficient number, since it is larger than the sum of its proper divisors (2468293313).

101200024111 is an equidigital number, since it uses as much as digits as its factorization.

101200024111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2468293312.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 101200024111 its reverse (111420002101), we get a palindrome (212620026212).

The spelling of 101200024111 in words is "one hundred one billion, two hundred million, twenty-four thousand, one hundred eleven".