101200211121113 has 8 divisors (see below), whose sum is σ = 110364397718400. Its totient is φ = 92233103805648.

The previous prime is 101200211121077. The next prime is 101200211121187. The reversal of 101200211121113 is 311121112002101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101200211121113 - 2⁸ = 101200211120857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101200211121091 and 101200211121100.

It is not an unprimeable number, because it can be changed into a prime (101200211121193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49269819383 + ... + 49269821436.

It is an arithmetic number, because the mean of its divisors is an integer number (13795549714800).

Almost surely, 2^{101200211121113} is an apocalyptic number.

101200211121113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

101200211121113 is a deficient number, since it is larger than the sum of its proper divisors (9164186597287).

101200211121113 is an equidigital number, since it uses as much as digits as its factorization.

101200211121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98539640911.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 101200211121113 its reverse (311121112002101), we get a palindrome (412321323123214).

The spelling of 101200211121113 in words is "one hundred one trillion, two hundred billion, two hundred eleven million, one hundred twenty-one thousand, one hundred thirteen".