1012010021341 has 4 divisors (see below), whose sum is σ = 1104010932384. Its totient is φ = 920009110300.

The previous prime is 1012010021303. The next prime is 1012010021377. The reversal of 1012010021341 is 1431200102101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1012010021341 - 2⁹ = 1012010020829 is a prime.

It is a super-2 number, since 2×1012010021341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012010021041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46000455505 + ... + 46000455526.

It is an arithmetic number, because the mean of its divisors is an integer number (276002733096).

Almost surely, 2^{1012010021341} is an apocalyptic number.

1012010021341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1012010021341 is a deficient number, since it is larger than the sum of its proper divisors (92000911043).

1012010021341 is an equidigital number, since it uses as much as digits as its factorization.

1012010021341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92000911042.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1012010021341 its reverse (1431200102101), we get a palindrome (2443210123442).

The spelling of 1012010021341 in words is "one trillion, twelve billion, ten million, twenty-one thousand, three hundred forty-one".