Base | Representation |
---|---|
bin | 10010110110011010… |
… | …01010010101011111 |
3 | 222010021202221001210 |
4 | 21123031022111133 |
5 | 131211222031310 |
6 | 4352113035503 |
7 | 505533346056 |
oct | 113315122537 |
9 | 28107687053 |
10 | 10120111455 |
11 | 43235a2583 |
12 | 1b65255b93 |
13 | c5385303c |
14 | 6c00ab39d |
15 | 3e36d6820 |
hex | 25b34a55f |
10120111455 has 16 divisors (see below), whose sum is σ = 17044398720. Its totient is φ = 5113319328.
The previous prime is 10120111453. The next prime is 10120111457. The reversal of 10120111455 is 55411102101.
It is an interprime number because it is at equal distance from previous prime (10120111453) and next prime (10120111457).
It is not a de Polignac number, because 10120111455 - 21 = 10120111453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10120111453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17754297 + ... + 17754866.
It is an arithmetic number, because the mean of its divisors is an integer number (1065274920).
Almost surely, 210120111455 is an apocalyptic number.
10120111455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10120111455 is a deficient number, since it is larger than the sum of its proper divisors (6924287265).
10120111455 is a wasteful number, since it uses less digits than its factorization.
10120111455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35509190.
The product of its (nonzero) digits is 200, while the sum is 21.
Adding to 10120111455 its reverse (55411102101), we get a palindrome (65531213556).
The spelling of 10120111455 in words is "ten billion, one hundred twenty million, one hundred eleven thousand, four hundred fifty-five".
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