1012012010111 has 4 divisors (see below), whose sum is σ = 1024822288800. Its totient is φ = 999201731424.

The previous prime is 1012012010017. The next prime is 1012012010129. The reversal of 1012012010111 is 1110102102101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1012012010111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012012010092 and 1012012010101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012012010011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6405139226 + ... + 6405139383.

It is an arithmetic number, because the mean of its divisors is an integer number (256205572200).

Almost surely, 2^{1012012010111} is an apocalyptic number.

1012012010111 is a deficient number, since it is larger than the sum of its proper divisors (12810278689).

1012012010111 is an equidigital number, since it uses as much as digits as its factorization.

1012012010111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12810278688.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1012012010111 its reverse (1110102102101), we get a palindrome (2122114112212).

The spelling of 1012012010111 in words is "one trillion, twelve billion, twelve million, ten thousand, one hundred eleven".