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101201211012000 = 25353116711442923
BaseRepresentation
bin10111000000101010111110…
…001110111011001110100000
3111021022202000101202102102110
4113000222332032323032200
5101231040040004341000
6555123110003315320
730213355231236441
oct2700527616731640
9437282011672373
10101201211012000
112a278213340530
12b42558097bb40
1344613055ac4a8
141adc2440d52c8
15ba772096d850
hex5c0abe3bb3a0

101201211012000 has 384 divisors, whose sum is σ = 367072890283008. Its totient is φ = 24167451264000.

The previous prime is 101201211011977. The next prime is 101201211012053. The reversal of 101201211012000 is 210112102101.

It is a super-2 number, since 2×1012012110120002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3122539 + ... + 14565461.

It is an arithmetic number, because the mean of its divisors is an integer number (955918985112).

Almost surely, 2101201211012000 is an apocalyptic number.

101201211012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101201211012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (183536445141504).

101201211012000 is an abundant number, since it is smaller than the sum of its proper divisors (265871679271008).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101201211012000 is a wasteful number, since it uses less digits than its factorization.

101201211012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11443029 (or 11443011 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 101201211012000 its reverse (210112102101), we get a palindrome (101411323114101).

It can be divided in two parts, 10120121 and 1012000, that added together give a triangular number (11132121 = T4718).

The spelling of 101201211012000 in words is "one hundred one trillion, two hundred one billion, two hundred eleven million, twelve thousand".