1012013011133 has 4 divisors (see below), whose sum is σ = 1012019193660. Its totient is φ = 1012006828608.

The previous prime is 1012013011099. The next prime is 1012013011151. The reversal of 1012013011133 is 3311103102101.

1012013011133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 993335142244 + 18677868889 = 996662^2 + 136667^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012013011133 - 2¹² = 1012013007037 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012013011153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2838860 + ... + 3175397.

It is an arithmetic number, because the mean of its divisors is an integer number (253004798415).

Almost surely, 2^{1012013011133} is an apocalyptic number.

It is an amenable number.

1012013011133 is a deficient number, since it is larger than the sum of its proper divisors (6182527).

1012013011133 is an equidigital number, since it uses as much as digits as its factorization.

1012013011133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6182526.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1012013011133 its reverse (3311103102101), we get a palindrome (4323116113234).

The spelling of 1012013011133 in words is "one trillion, twelve billion, thirteen million, eleven thousand, one hundred thirty-three".