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1012013210122 = 2571886176191
BaseRepresentation
bin11101011101000001011…
…00000001101000001010
310120202011221101201201021
432232200230001220022
5113040100340210442
62052525031143054
7133054426232155
oct16564054015012
93522157351637
101012013210122
1136021308a522
12144175214a8a
13745810a70b5
1436da5b02c9c
151b4d1245e67
hexeba0b01a0a

1012013210122 has 8 divisors (see below), whose sum is σ = 1520678345472. Its totient is φ = 505120428300.

The previous prime is 1012013210099. The next prime is 1012013210123. The reversal of 1012013210122 is 2210123102101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×10120132101222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1012013210096 and 1012013210105.

It is not an unprimeable number, because it can be changed into a prime (1012013210123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443086954 + ... + 443089237.

It is an arithmetic number, because the mean of its divisors is an integer number (190084793184).

Almost surely, 21012013210122 is an apocalyptic number.

1012013210122 is a deficient number, since it is larger than the sum of its proper divisors (508665135350).

1012013210122 is an equidigital number, since it uses as much as digits as its factorization.

1012013210122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 886176764.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1012013210122 its reverse (2210123102101), we get a palindrome (3222136312223).

The spelling of 1012013210122 in words is "one trillion, twelve billion, thirteen million, two hundred ten thousand, one hundred twenty-two".

Divisors: 1 2 571 1142 886176191 1772352382 506006605061 1012013210122