Base | Representation |
---|---|
bin | 10010110110011010… |
… | …10010001000110101 |
3 | 222010021211112220102 |
4 | 21123031102020311 |
5 | 131211224042123 |
6 | 4352113443445 |
7 | 505533541202 |
oct | 113315221065 |
9 | 28107745812 |
10 | 10120143413 |
11 | 4323614596 |
12 | 1b65270585 |
13 | c53864753 |
14 | 6c00b8ca9 |
15 | 3e36e1028 |
hex | 25b352235 |
10120143413 has 4 divisors (see below), whose sum is σ = 10652782560. Its totient is φ = 9587504268.
The previous prime is 10120143403. The next prime is 10120143431. The reversal of 10120143413 is 31434102101.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10120143413 is a prime.
It is a super-3 number, since 3×101201434133 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10120143403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266319545 + ... + 266319582.
It is an arithmetic number, because the mean of its divisors is an integer number (2663195640).
Almost surely, 210120143413 is an apocalyptic number.
It is an amenable number.
10120143413 is a deficient number, since it is larger than the sum of its proper divisors (532639147).
10120143413 is an equidigital number, since it uses as much as digits as its factorization.
10120143413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 532639146.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 10120143413 its reverse (31434102101), we get a palindrome (41554245514).
The spelling of 10120143413 in words is "ten billion, one hundred twenty million, one hundred forty-three thousand, four hundred thirteen".
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