Search a number
-
+
10120193 = 21147963
BaseRepresentation
bin100110100110…
…110000000001
3201001011021222
4212212300001
510042321233
61000524425
7152006636
oct46466001
921034258
1010120193
1157924a6
123480715
1321344a5
1414b618d
15d4d898
hex9a6c01

10120193 has 4 divisors (see below), whose sum is σ = 10168368. Its totient is φ = 10072020.

The previous prime is 10120183. The next prime is 10120199. The reversal of 10120193 is 39102101.

It is a happy number.

10120193 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39102101 = 355710993.

It is a cyclic number.

It is not a de Polignac number, because 10120193 - 212 = 10116097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10120199) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23771 + ... + 24192.

It is an arithmetic number, because the mean of its divisors is an integer number (2542092).

Almost surely, 210120193 is an apocalyptic number.

It is an amenable number.

10120193 is a deficient number, since it is larger than the sum of its proper divisors (48175).

10120193 is an equidigital number, since it uses as much as digits as its factorization.

10120193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48174.

The product of its (nonzero) digits is 54, while the sum is 17.

The square root of 10120193 is about 3181.2250784878. The cubic root of 10120193 is about 216.3031936146.

Adding to 10120193 its reverse (39102101), we get a palindrome (49222294).

The spelling of 10120193 in words is "ten million, one hundred twenty thousand, one hundred ninety-three".

Divisors: 1 211 47963 10120193