1012022133 has 4 divisors (see below), whose sum is σ = 1349362848. Its totient is φ = 674681420.

The previous prime is 1012022131. The next prime is 1012022161. The reversal of 1012022133 is 3312202101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1012022133 - 2¹ = 1012022131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012022131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168670353 + ... + 168670358.

It is an arithmetic number, because the mean of its divisors is an integer number (337340712).

Almost surely, 2^1012022133 is an apocalyptic number.

It is an amenable number.

1012022133 is a deficient number, since it is larger than the sum of its proper divisors (337340715).

1012022133 is an equidigital number, since it uses as much as digits as its factorization.

1012022133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 337340714.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 1012022133 is about 31812.2953117187. The cubic root of 1012022133 is about 1003.9914249967.

Adding to 1012022133 its reverse (3312202101), we get a palindrome (4324224234).

The spelling of 1012022133 in words is "one billion, twelve million, twenty-two thousand, one hundred thirty-three".