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1012022200303 = 5571816915979
BaseRepresentation
bin11101011101000010011…
…10010100011111101111
310120202012120022110220221
432232201032110133233
5113040110140402203
62052525551552211
7133054565524462
oct16564116243757
93522176273827
101012022200303
1136021816aa24
1214417822b667
1374582c0412a
1436da6da32d9
151b4d1e1eabd
hexeba13947ef

1012022200303 has 4 divisors (see below), whose sum is σ = 1013839116840. Its totient is φ = 1010205283768.

The previous prime is 1012022200159. The next prime is 1012022200307. The reversal of 1012022200303 is 3030022202101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1012022200303 is a prime.

It is a super-2 number, since 2×10120222003032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012022200307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 908457433 + ... + 908458546.

It is an arithmetic number, because the mean of its divisors is an integer number (253459779210).

Almost surely, 21012022200303 is an apocalyptic number.

1012022200303 is a deficient number, since it is larger than the sum of its proper divisors (1816916537).

1012022200303 is an equidigital number, since it uses as much as digits as its factorization.

1012022200303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1816916536.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 1012022200303 its reverse (3030022202101), we get a palindrome (4042044402404).

The spelling of 1012022200303 in words is "one trillion, twelve billion, twenty-two million, two hundred thousand, three hundred three".

Divisors: 1 557 1816915979 1012022200303