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10120244352151 = 17595308491303
BaseRepresentation
bin1001001101000100110110…
…0100011101010010010111
31022211111010020012020110111
42103101031210131102113
52311302230023232101
633305102010503451
72063110042436533
oct223211544352227
938744106166414
1010120244352151
113251a7611456a
121175455434b87
13585447b5865b
1426db72ac0bc3
151283b65b4251
hex9344d91d497

10120244352151 has 4 divisors (see below), whose sum is σ = 10715552843472. Its totient is φ = 9524935860832.

The previous prime is 10120244352149. The next prime is 10120244352167. The reversal of 10120244352151 is 15125344202101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10120244352151 - 21 = 10120244352149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10120244356151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297654245635 + ... + 297654245668.

It is an arithmetic number, because the mean of its divisors is an integer number (2678888210868).

Almost surely, 210120244352151 is an apocalyptic number.

10120244352151 is a deficient number, since it is larger than the sum of its proper divisors (595308491321).

10120244352151 is an equidigital number, since it uses as much as digits as its factorization.

10120244352151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 595308491320.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 10120244352151 its reverse (15125344202101), we get a palindrome (25245588554252).

The spelling of 10120244352151 in words is "ten trillion, one hundred twenty billion, two hundred forty-four million, three hundred fifty-two thousand, one hundred fifty-one".

Divisors: 1 17 595308491303 10120244352151