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1012040113 = 7331577757
BaseRepresentation
bin111100010100101…
…000000110110001
32121112022222001011
4330110220012301
54033040240423
6244231310521
734036125160
oct7424500661
92545288034
101012040113
1147a2a7797
12242b1b441
13131894506
14985a33d7
155dcadb0d
hex3c5281b1

1012040113 has 16 divisors (see below), whose sum is σ = 1163657344. Its totient is φ = 862202880.

The previous prime is 1012040087. The next prime is 1012040123. The reversal of 1012040113 is 3110402101.

It is a de Polignac number, because none of the positive numbers 2k-1012040113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012040093 and 1012040102.

It is not an unprimeable number, because it can be changed into a prime (1012040123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1336531 + ... + 1337287.

It is an arithmetic number, because the mean of its divisors is an integer number (72728584).

Almost surely, 21012040113 is an apocalyptic number.

It is an amenable number.

1012040113 is a deficient number, since it is larger than the sum of its proper divisors (151617231).

1012040113 is an equidigital number, since it uses as much as digits as its factorization.

1012040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1672.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1012040113 is about 31812.5779056021. The cubic root of 1012040113 is about 1003.9973707359.

Adding to 1012040113 its reverse (3110402101), we get a palindrome (4122442214).

The spelling of 1012040113 in words is "one billion, twelve million, forty thousand, one hundred thirteen".

Divisors: 1 7 331 577 757 2317 4039 5299 190987 250567 436789 1336909 1753969 3057523 144577159 1012040113