1012112113 has 4 divisors (see below), whose sum is σ = 1035649648. Its totient is φ = 988574580.

The previous prime is 1012112099. The next prime is 1012112141. The reversal of 1012112113 is 3112112101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112112101 = 7 ⋅444587443.

It is a cyclic number.

It is not a de Polignac number, because 1012112113 - 2⁹ = 1012111601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012112093 and 1012112102.

It is not an unprimeable number, because it can be changed into a prime (1012112173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11768703 + ... + 11768788.

It is an arithmetic number, because the mean of its divisors is an integer number (258912412).

Almost surely, 2^1012112113 is an apocalyptic number.

It is an amenable number.

1012112113 is a deficient number, since it is larger than the sum of its proper divisors (23537535).

1012112113 is an equidigital number, since it uses as much as digits as its factorization.

1012112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23537534.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1012112113 is about 31813.7095133529. The cubic root of 1012112113 is about 1004.0211794419.

Subtracting from 1012112113 its product of nonzero digits (12), we obtain a palindrome (1012112101).

Adding to 1012112113 its reverse (3112112101), we get a palindrome (4124224214).

The spelling of 1012112113 in words is "one billion, twelve million, one hundred twelve thousand, one hundred thirteen".