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10121564113 = 32119315127
BaseRepresentation
bin10010110110100101…
…01100111111010001
3222010101111201201221
421123102230333101
5131212110022423
64352204125041
7505551606163
oct113322547721
928111451657
1010121564113
1143243a4a21
121b65836781
13c53c412bb
146c0368933
153e38c1e5d
hex25b4acfd1

10121564113 has 4 divisors (see below), whose sum is σ = 10121911360. Its totient is φ = 10121216868.

The previous prime is 10121564083. The next prime is 10121564147. The reversal of 10121564113 is 31146512101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31146512101 = 117192657779.

It is a cyclic number.

It is not a de Polignac number, because 10121564113 - 213 = 10121555921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10121564153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125445 + ... + 189682.

It is an arithmetic number, because the mean of its divisors is an integer number (2530477840).

Almost surely, 210121564113 is an apocalyptic number.

It is an amenable number.

10121564113 is a deficient number, since it is larger than the sum of its proper divisors (347247).

10121564113 is an equidigital number, since it uses as much as digits as its factorization.

10121564113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 347246.

The product of its (nonzero) digits is 720, while the sum is 25.

The spelling of 10121564113 in words is "ten billion, one hundred twenty-one million, five hundred sixty-four thousand, one hundred thirteen".

Divisors: 1 32119 315127 10121564113