10122213133 has 4 divisors (see below), whose sum is σ = 10122417760. Its totient is φ = 10122008508.

The previous prime is 10122213119. The next prime is 10122213163. The reversal of 10122213133 is 33131222101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33131222101 = 71 ⋅466636931.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10122213133 is a prime.

It is a super-3 number, since 3×10122213133³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10122213133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10122213163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23266 + ... + 144172.

It is an arithmetic number, because the mean of its divisors is an integer number (2530604440).

Almost surely, 2^10122213133 is an apocalyptic number.

It is an amenable number.

10122213133 is a deficient number, since it is larger than the sum of its proper divisors (204627).

10122213133 is an equidigital number, since it uses as much as digits as its factorization.

10122213133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 204626.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10122213133 its reverse (33131222101), we get a palindrome (43253435234).

The spelling of 10122213133 in words is "ten billion, one hundred twenty-two million, two hundred thirteen thousand, one hundred thirty-three".