Base | Representation |
---|---|
bin | 10010110110110000… |
… | …01110010011100111 |
3 | 222010111020020220120 |
4 | 21123120032103213 |
5 | 131212442330203 |
6 | 4352255133023 |
7 | 505600114326 |
oct | 113330162347 |
9 | 28114206816 |
10 | 10123011303 |
11 | 43251a3249 |
12 | 1b66214173 |
13 | c54329c22 |
14 | 6c06240bd |
15 | 3e3aaab53 |
hex | 25b60e4e7 |
10123011303 has 8 divisors (see below), whose sum is σ = 13583319408. Its totient is φ = 6705688704.
The previous prime is 10123011209. The next prime is 10123011319. The reversal of 10123011303 is 30311032101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10123011303 - 214 = 10122994919 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10123011383) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10745826 + ... + 10746767.
It is an arithmetic number, because the mean of its divisors is an integer number (1697914926).
Almost surely, 210123011303 is an apocalyptic number.
10123011303 is a deficient number, since it is larger than the sum of its proper divisors (3460308105).
10123011303 is a wasteful number, since it uses less digits than its factorization.
10123011303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21492753.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10123011303 its reverse (30311032101), we get a palindrome (40434043404).
The spelling of 10123011303 in words is "ten billion, one hundred twenty-three million, eleven thousand, three hundred three".
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