Base | Representation |
---|---|
bin | 101111001000111110… |
… | …1101000010101000111 |
3 | 100200022002221022120220 |
4 | 1132101331220111013 |
5 | 3124311133200403 |
6 | 114301132355423 |
7 | 10212436103352 |
oct | 1362175502507 |
9 | 320262838526 |
10 | 101233100103 |
11 | 39a2949a4a3 |
12 | 17752915b73 |
13 | 9714122c85 |
14 | 4c84b29299 |
15 | 2977612953 |
hex | 1791f68547 |
101233100103 has 4 divisors (see below), whose sum is σ = 134977466808. Its totient is φ = 67488733400.
The previous prime is 101233100099. The next prime is 101233100117. The reversal of 101233100103 is 301001332101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 101233100103 - 22 = 101233100099 is a prime.
It is a super-2 number, since 2×1012331001032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101233100173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16872183348 + ... + 16872183353.
It is an arithmetic number, because the mean of its divisors is an integer number (33744366702).
Almost surely, 2101233100103 is an apocalyptic number.
101233100103 is a deficient number, since it is larger than the sum of its proper divisors (33744366705).
101233100103 is an equidigital number, since it uses as much as digits as its factorization.
101233100103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33744366704.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 101233100103 its reverse (301001332101), we get a palindrome (402234432204).
The spelling of 101233100103 in words is "one hundred one billion, two hundred thirty-three million, one hundred thousand, one hundred three".
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