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101240342013 = 333746780671
BaseRepresentation
bin101111001001001100…
…1010000010111111101
3100200022121120020121210
41132102121100113331
53124320011421023
6114301551515033
710212554464656
oct1362231202775
9320277506553
10101240342013
1139a32596448
1217755228a79
13971578a325
144c85a9252d
152978093593
hex17926505fd

101240342013 has 4 divisors (see below), whose sum is σ = 134987122688. Its totient is φ = 67493561340.

The previous prime is 101240341999. The next prime is 101240342053. The reversal of 101240342013 is 310243042101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 101240342013 - 26 = 101240341949 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101240342053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16873390333 + ... + 16873390338.

It is an arithmetic number, because the mean of its divisors is an integer number (33746780672).

Almost surely, 2101240342013 is an apocalyptic number.

It is an amenable number.

101240342013 is a deficient number, since it is larger than the sum of its proper divisors (33746780675).

101240342013 is an equidigital number, since it uses as much as digits as its factorization.

101240342013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33746780674.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 101240342013 its reverse (310243042101), we get a palindrome (411483384114).

The spelling of 101240342013 in words is "one hundred one billion, two hundred forty million, three hundred forty-two thousand, thirteen".

Divisors: 1 3 33746780671 101240342013