Base | Representation |
---|---|
bin | 101111001010111110… |
… | …1010010111000011001 |
3 | 100200110210001100010112 |
4 | 1132111331102320121 |
5 | 3124430312333423 |
6 | 114311525054105 |
7 | 10214211552032 |
oct | 1362575227031 |
9 | 320423040115 |
10 | 101300121113 |
11 | 39a63306364 |
12 | 17771257335 |
13 | 9724c8a889 |
14 | 4c8d9b3a89 |
15 | 297d450a78 |
hex | 1795f52e19 |
101300121113 has 4 divisors (see below), whose sum is σ = 101439461760. Its totient is φ = 101160780468.
The previous prime is 101300121031. The next prime is 101300121193. The reversal of 101300121113 is 311121003101.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 101300121113 - 218 = 101299858969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101300121193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69669233 + ... + 69670686.
It is an arithmetic number, because the mean of its divisors is an integer number (25359865440).
Almost surely, 2101300121113 is an apocalyptic number.
It is an amenable number.
101300121113 is a deficient number, since it is larger than the sum of its proper divisors (139340647).
101300121113 is an equidigital number, since it uses as much as digits as its factorization.
101300121113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 139340646.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 101300121113 its reverse (311121003101), we get a palindrome (412421124214).
The spelling of 101300121113 in words is "one hundred one billion, three hundred million, one hundred twenty-one thousand, one hundred thirteen".
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