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10130012113221 = 3571113227183461
BaseRepresentation
bin1001001101101001001111…
…0001100000100101000101
31022212102022221221220200000
42103122103301200211011
52311432231100110341
633313355135511513
72063604100152210
oct223322361404505
938772287856600
1010130012113221
113256128826a80
121177320688599
135863436b1730
1427041c06c777
15128788d9a8b6
hex93693c60945

10130012113221 has 192 divisors, whose sum is σ = 20463580440576. Its totient is φ = 4836123014400.

The previous prime is 10130012113213. The next prime is 10130012113231. The reversal of 10130012113221 is 12231121003101.

10130012113221 is a `hidden beast` number, since 1 + 0 + 130 + 0 + 1 + 211 + 322 + 1 = 666.

It is not a de Polignac number, because 10130012113221 - 23 = 10130012113213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10130012113194 and 10130012113203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10130012113231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 55124431 + ... + 55307891.

It is an arithmetic number, because the mean of its divisors is an integer number (106581148128).

Almost surely, 210130012113221 is an apocalyptic number.

10130012113221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10130012113221 is an abundant number, since it is smaller than the sum of its proper divisors (10333568327355).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10130012113221 is a wasteful number, since it uses less digits than its factorization.

10130012113221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183734 (or 183722 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 10130012113221 its reverse (12231121003101), we get a palindrome (22361133116322).

The spelling of 10130012113221 in words is "ten trillion, one hundred thirty billion, twelve million, one hundred thirteen thousand, two hundred twenty-one".