10130324412433 has 4 divisors (see below), whose sum is σ = 10321462608948. Its totient is φ = 9939186215920.

The previous prime is 10130324412421. The next prime is 10130324412457. The reversal of 10130324412433 is 33421442303101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8508848162049 + 1621476250384 = 2916993^2 + 1273372^2 .

It is a cyclic number.

It is not a de Polignac number, because 10130324412433 - 2⁵ = 10130324412401 is a prime.

It is a super-2 number, since 2×10130324412433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10130324412395 and 10130324412404.

It is not an unprimeable number, because it can be changed into a prime (10130324412413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95569098178 + ... + 95569098283.

It is an arithmetic number, because the mean of its divisors is an integer number (2580365652237).

Almost surely, 2^{10130324412433} is an apocalyptic number.

It is an amenable number.

10130324412433 is a deficient number, since it is larger than the sum of its proper divisors (191138196515).

10130324412433 is an equidigital number, since it uses as much as digits as its factorization.

10130324412433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191138196514.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 10130324412433 its reverse (33421442303101), we get a palindrome (43551766715534).

The spelling of 10130324412433 in words is "ten trillion, one hundred thirty billion, three hundred twenty-four million, four hundred twelve thousand, four hundred thirty-three".