10131003100113 has 16 divisors (see below), whose sum is σ = 15596870755200. Its totient is φ = 5729462724096.

The previous prime is 10131003100081. The next prime is 10131003100147. The reversal of 10131003100113 is 31100130013101.

It is not a de Polignac number, because 10131003100113 - 2⁵ = 10131003100081 is a prime.

It is a super-2 number, since 2×10131003100113² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10131003100092 and 10131003100101.

It is not an unprimeable number, because it can be changed into a prime (10131003100193) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2486743938 + ... + 2486748011.

It is an arithmetic number, because the mean of its divisors is an integer number (974804422200).

Almost surely, 2^{10131003100113} is an apocalyptic number.

It is an amenable number.

10131003100113 is a deficient number, since it is larger than the sum of its proper divisors (5465867655087).

10131003100113 is an equidigital number, since it uses as much as digits as its factorization.

10131003100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4973492056.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 10131003100113 its reverse (31100130013101), we get a palindrome (41231133113214).

The spelling of 10131003100113 in words is "ten trillion, one hundred thirty-one billion, three million, one hundred thousand, one hundred thirteen".