101310402013031 has 4 divisors (see below), whose sum is σ = 101312656456200. Its totient is φ = 101308147569864.

The previous prime is 101310402012997. The next prime is 101310402013039. The reversal of 101310402013031 is 130310204013101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101310402013031 is a prime.

It is a super-2 number, since 2×101310402013031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101310402012994 and 101310402013012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101310402013039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1127154176 + ... + 1127244053.

It is an arithmetic number, because the mean of its divisors is an integer number (25328164114050).

Almost surely, 2^{101310402013031} is an apocalyptic number.

101310402013031 is a deficient number, since it is larger than the sum of its proper divisors (2254443169).

101310402013031 is an equidigital number, since it uses as much as digits as its factorization.

101310402013031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2254443168.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 101310402013031 its reverse (130310204013101), we get a palindrome (231620606026132).

The spelling of 101310402013031 in words is "one hundred one trillion, three hundred ten billion, four hundred two million, thirteen thousand, thirty-one".