101312003113 has 4 divisors (see below), whose sum is σ = 101346905088. Its totient is φ = 101277101140.

The previous prime is 101312003059. The next prime is 101312003161. The reversal of 101312003113 is 311300213101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311300213101 = 37 ⋅8413519273.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101312003113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101312003173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17446633 + ... + 17452438.

It is an arithmetic number, because the mean of its divisors is an integer number (25336726272).

Almost surely, 2^101312003113 is an apocalyptic number.

It is an amenable number.

101312003113 is a deficient number, since it is larger than the sum of its proper divisors (34901975).

101312003113 is an equidigital number, since it uses as much as digits as its factorization.

101312003113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34901974.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 101312003113 its reverse (311300213101), we get a palindrome (412612216214).

The spelling of 101312003113 in words is "one hundred one billion, three hundred twelve million, three thousand, one hundred thirteen".