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101312003114 = 277236571651
BaseRepresentation
bin101111001011010101…
…0100111110000101010
3100200111121102000011122
41132112222213300222
53124441333044424
6114313031455242
710214414550320
oct1362652476052
9320447360148
10101312003114
1139a69a914a3
1217775227522
13972758ac4a
144c913c7d10
15297e4eb45e
hex1796aa7c2a

101312003114 has 8 divisors (see below), whose sum is σ = 173677719648. Its totient is φ = 43419429900.

The previous prime is 101312003059. The next prime is 101312003161. The reversal of 101312003114 is 411300213101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1013120031142 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101312003092 and 101312003101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3618285812 + ... + 3618285839.

It is an arithmetic number, because the mean of its divisors is an integer number (21709714956).

Almost surely, 2101312003114 is an apocalyptic number.

101312003114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

101312003114 is a deficient number, since it is larger than the sum of its proper divisors (72365716534).

101312003114 is an equidigital number, since it uses as much as digits as its factorization.

101312003114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7236571660.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 101312003114 its reverse (411300213101), we get a palindrome (512612216215).

The spelling of 101312003114 in words is "one hundred one billion, three hundred twelve million, three thousand, one hundred fourteen".

Divisors: 1 2 7 14 7236571651 14473143302 50656001557 101312003114