1013212113 has 4 divisors (see below), whose sum is σ = 1350949488. Its totient is φ = 675474740.

The previous prime is 1013212061. The next prime is 1013212129. The reversal of 1013212113 is 3112123101.

It is a happy number.

1013212113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1013212113 - 2¹³ = 1013203921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1013212092 and 1013212101.

It is not an unprimeable number, because it can be changed into a prime (1013212163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168868683 + ... + 168868688.

It is an arithmetic number, because the mean of its divisors is an integer number (337737372).

Almost surely, 2^1013212113 is an apocalyptic number.

It is an amenable number.

1013212113 is a deficient number, since it is larger than the sum of its proper divisors (337737375).

1013212113 is an equidigital number, since it uses as much as digits as its factorization.

1013212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 337737374.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 1013212113 is about 31830.9929628342. The cubic root of 1013212113 is about 1004.3847832415.

Adding to 1013212113 its reverse (3112123101), we get a palindrome (4125335214).

The spelling of 1013212113 in words is "one billion, thirteen million, two hundred twelve thousand, one hundred thirteen".