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101321300341 = 538311882211
BaseRepresentation
bin101111001011100111…
…0000101100101110101
3100200112020220100120101
41132113032011211311
53130001223102331
6114314003034101
710214556562042
oct1362716054565
9320466810511
10101321300341
1139a74261658
121777836b931
139729494971
144c927281c9
152980236061
hex1797385975

101321300341 has 4 divisors (see below), whose sum is σ = 101323236384. Its totient is φ = 101319364300.

The previous prime is 101321300329. The next prime is 101321300369. The reversal of 101321300341 is 143003123101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101321300341 is a prime.

It is a super-2 number, since 2×1013213003412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101321300141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 887275 + ... + 994936.

It is an arithmetic number, because the mean of its divisors is an integer number (25330809096).

Almost surely, 2101321300341 is an apocalyptic number.

It is an amenable number.

101321300341 is a deficient number, since it is larger than the sum of its proper divisors (1936043).

101321300341 is an equidigital number, since it uses as much as digits as its factorization.

101321300341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1936042.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 101321300341 its reverse (143003123101), we get a palindrome (244324423442).

The spelling of 101321300341 in words is "one hundred one billion, three hundred twenty-one million, three hundred thousand, three hundred forty-one".

Divisors: 1 53831 1882211 101321300341