Base | Representation |
---|---|
bin | 1001001101110001111010… |
… | …0001101100101010011001 |
3 | 1022212122100012021212221221 |
4 | 2103130132201230222121 |
5 | 2312002013020021213 |
6 | 33314422134332041 |
7 | 2064015554655256 |
oct | 223343641545231 |
9 | 38778305255857 |
10 | 10132340001433 |
11 | 3257112865931 |
12 | 11778701ba021 |
13 | 586624a6c590 |
14 | 27059d2ba42d |
15 | 12887342a38d |
hex | 9371e86ca99 |
10132340001433 has 8 divisors (see below), whose sum is σ = 11486053443200. Its totient is φ = 8860669798608.
The previous prime is 10132340001431. The next prime is 10132340001437. The reversal of 10132340001433 is 33410004323101.
10132340001433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10132340001433 - 21 = 10132340001431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10132340001398 and 10132340001407.
It is not an unprimeable number, because it can be changed into a prime (10132340001431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20510809473 + ... + 20510809966.
It is an arithmetic number, because the mean of its divisors is an integer number (1435756680400).
Almost surely, 210132340001433 is an apocalyptic number.
10132340001433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10132340001433 is a deficient number, since it is larger than the sum of its proper divisors (1353713441767).
10132340001433 is a wasteful number, since it uses less digits than its factorization.
10132340001433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41021619471.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 10132340001433 its reverse (33410004323101), we get a palindrome (43542344324534).
The spelling of 10132340001433 in words is "ten trillion, one hundred thirty-two billion, three hundred forty million, one thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •