101330100113 has 4 divisors (see below), whose sum is σ = 110541927408. Its totient is φ = 92118272820.

The previous prime is 101330100083. The next prime is 101330100133. The reversal of 101330100113 is 311001033101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101330100113 is a prime.

It is a super-2 number, since 2×101330100113² (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (101330100133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4605913631 + ... + 4605913652.

It is an arithmetic number, because the mean of its divisors is an integer number (27635481852).

Almost surely, 2^101330100113 is an apocalyptic number.

It is an amenable number.

101330100113 is a deficient number, since it is larger than the sum of its proper divisors (9211827295).

101330100113 is an equidigital number, since it uses as much as digits as its factorization.

101330100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9211827294.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 101330100113 its reverse (311001033101), we get a palindrome (412331133214).

The spelling of 101330100113 in words is "one hundred one billion, three hundred thirty million, one hundred thousand, one hundred thirteen".