101331131010221 has 4 divisors (see below), whose sum is σ = 115807006868832. Its totient is φ = 86855255151612.

The previous prime is 101331131010211. The next prime is 101331131010301. The reversal of 101331131010221 is 122010131133101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101331131010221 - 2¹⁴ = 101331130993837 is a prime.

It is a super-2 number, since 2×101331131010221² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101331131010193 and 101331131010202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101331131010211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7237937929295 + ... + 7237937929308.

It is an arithmetic number, because the mean of its divisors is an integer number (28951751717208).

Almost surely, 2^{101331131010221} is an apocalyptic number.

It is an amenable number.

101331131010221 is a deficient number, since it is larger than the sum of its proper divisors (14475875858611).

101331131010221 is an equidigital number, since it uses as much as digits as its factorization.

101331131010221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14475875858610.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 101331131010221 its reverse (122010131133101), we get a palindrome (223341262143322).

The spelling of 101331131010221 in words is "one hundred one trillion, three hundred thirty-one billion, one hundred thirty-one million, ten thousand, two hundred twenty-one".